ELI5: why does airflow speed up when flowing over a wing?
I mean, I get that in order to get back next to the airmolecule that took the bottom path under the wing, and the path on top beeing longer results in a faster speed and therefore a lower pressure (because the energy for that needs to come from somewhere), but why does it do that in the first place?
What's causing the air to speed up suddenly instead of building pressure above the wing, due to it deflecting air up?
Posted Nov 9, 2023, 8:56 PM UTC
It speeds up because it's flowing into a lower pressure area, not the other way around. The most important factor that causes that change in pressure is the angle of attack. The energy is coming from the wing's movement through the air.
Length of the side has nothing to do with it, as the air at the leading edge of the wing doesn't know how long the sides are, and the air on the top of the wing doesn't have to meet back up with the air on the bottom of the wing.
Ohhhhh, the wing pushes the air away, causing a low pressure just behind/above it. Totally overlooked that
There are a lot of right and wrong explanations of lift, but equal transit theory is extra wrong.
No offense, but it's easier to just start over on understanding lift and (as the cliché goes) forget everything you think you know about it.
https://ocw.mit.edu/courses/16-687-private-pilot-ground-school-january-iap-2019/resources/lecture-2-airplane-aerodynamics/
https://www1.grc.nasa.gov/beginners-guide-to-aeronautics/aerodynamic-forces/
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I forgot to write additional explanation sufficient for rule 3, so here's what I linked to. I'm not sure exactly where your misunderstanding lies, but all should be explained through these.
To some extent it does though.
If an airfoil is just sitting in the air, air molecules are happily bouncing around in their own little areas.
As it starts to move forward the the fluid some of the fluid goes over the top, some goes under the wing. Lets imagine that the fluid going over the top of the wing with the 'longer' path, didn't speed up. So its 'partner' molecule on the bottom of the wing got to the trailing edge first.
That means there is now a gap that needs to be filled. That creates the low pressure area you describe that speeds up the air.
If the air on the top were going faster and getting ahead of the the air on the bottom, you would have a high pressure area that would form and slow it down.
So it doesn't have to match up exactly, but to maintain a steady state, its going to end up doing roughly that.
It doesn't. The air flowing over the top of the wing will arrive at the trailing edge well ahead of the air flowing under the wing.
Moreover, as a consequence of the Kutta Joukowski theorem, it can be shown that if the air does meet up again at the trailing edge then the lift on the wing is zero.
As others have pointed out, this isn't the case. But since seeing is believing, here's a short video (1m15s) where you can actually see the top air beating the bottom air to the finish line: https://youtu.be/UqBmdZ-BNig?si=rXjzcueDv8obSVXg
You can see the vortices formed at trailing edge, particularly evident because it is at such a high angle of attack. That vortex is caused by the difference in velocities and is your induced drag. An efficient wing doesn't have nearly as much of that.
In a more efficient wing at a lower angle of attack, you are going to get a lot less of a vortex because it will be less disruptive to the steady state of the air right?
You still get a lot of vortex. You can find pictures online of passenger jets flying through clouds and such, and see the vortices. (I'm too mentally zonked right now to look them up myself, sorry!)
No, this isn't right. You're mixing up a few different concepts. Those vortices you see in that clip are ultimately caused by viscous friction between the air and the wing - they do contribute to drag, but not *induced drag.
In an ideal flow without friction, the upper and lower pressures are equal at the trailing edge (this is known as the Kutta condition), and therefore the velocities are also the same. Air flowing over the top surface of the wing will speed up as it flows into the low pressure region above the wing, then slow down again as it approaches the trailing edge, while the air flowing under the wing does the opposite. The air flowing over the upper surface takes significantly less time to flow over the wing, but when the two flows meet at the trailing edge they have the same speed.
What is happening in the video above is that friction with the wings surface slows down the air close to the surface of the wing. This region of slowed air is called the boundary layer. This creates a difference in velocity between the air close to the wing and the air further away, and that is what causes the vortices you are seeing. This turbulence is highly undesirable because it does indeed increase drag, but it is also unavoidable - at the Reynolds numbers typical of any full size aircraft, your boundary layer will be turbulent. The drag created is called "parasitic drag".
Induced drag is something different. Lift induced drag is the drag created as a direct result of lift production - i.e as a result of the deflection of the airflow by the wing which gives rise to lift. A perfectly frictionless wing would have no parasitic drag, but would still have induced drag, and induced drag increases the more lift is being produced. It is induced drag that is minimized by having a high aspect ratio wing.
Induced drag is related to the formation of vortices, but those vortices rotate around an axis parallel to the direction of travel of the wing. So they wouldn't be visible in the above video looking side on - you would see them in a view from behind the wing. In fact, for a wing which spans the entire width of the wind tunnel, which is probably what you are seeing in the above video, the induced drag will be zero as the aspect ratio is effectively infinite. This is often done in order to study the properties of an airfoil profile independent of the 3D shape of the wing.
Lets say you have two hoses, with the same mass of air being pumped into one end every second. The throughput at the outlet has to match, but the amount of time a bit of air takes to get through each hose can be dramatically different, as can the speed it travels inside the hose. Even if the hoses are the same length and diameter, if one is twice the pressure, then a packet of air will take twice as long to get through it.
If the hoses are the same length and diameter, but the rate one is being pumped causes it to be twisted the pressure then your original claim that the same mass is being pumped into them every second is false.
The only way to achieve a higher pressure with two hoses of the same length and diameter is to pump more mass.
I didn't say the exit was unrestricted.
Nah air going over top reaches their faster.
No reason you wouldn’t be able to have a tiny temporary high pressure area