Help understanding solar panel : accumulator ratio

I'm doing some math for the ratios and keep getting 23.8 panels to 25.2 accumulators. Everyone else has more panels than accumulators, but I have no idea what I'm doing wrong. Can you guys help? Math below:

Target power: 1MW

Required items for 1MW output

• Panels required: 16.667
  • (1000kW/MW) / (60kW/panel) = 16.667 panels/MW
• Accumulators required: 3.333
  • (1000kW/MW) / (300kW/accumulator) = 3.333 accumulators/MW
• Accumulator discharge time = 16.667s
  • 300kW/5MJ = 16.667s

Seconds of downtime to make up for = 126s

• Potential full power duration - average actual full power duration = average actual 0 power duration
  • Phase duration - phase duration * actual power output/potential power output = average actual 0 power duration
  • 210s - 210s * (60kW/60kW) + 84s - 84s * (30kW/60kW) + 42s - 42s * (0kW/60kW) + 84s - 84s * (30kW/60kW)
  • 0s + 42s + 42s + 42s = 126s of 0 power output

Items required to compensate for lost output (assuming 1MJ/s)

• Panels: 7.56
  • (126s/night) / (16.667 panels/MW) = 7.56 panels/night
• Accumulators: 25.2
  • (126s/night) * (1MJ/s) * (1 accumulator/5MJ) = 25.2 accumulators/night
  • (126s/night) * (1MJ/s) * (1 charge cycle/16.667s) * (3.333 accumulators/MW)
  • (126s/night) * (1MJ/s) * (1 accumulator/5MJ) = 25.2 accumulators/night

Extra panels required to charge 25.2 accumulators = 7.14 panels

• Average duration of solar panel full power output per day: 294s
• Power produced by 1 solar panel per day: 17.64MJ
• 60kW/panel * 294s/day = 17.64MJ/day/panel

Panels required to supply 126MJ to accumulators (assuming 294s of power production and 60kW of power per panel) = 7.14 panels

• 126MJ/night / 17.64MJ/day/panel = 7.14 panels/day to supply 126MJ/night

Total panels required to sustain 1MW all day = 23.8 panels

• 16.667 panels/1MW/day + 7.14 panels/126MJ/night = 23.8 panels

Accumulator : Panel ratio = 25:24

• 25.2 accumulators : 23.8 panels = 25 accumulators : 24 panels