The speed of N & Uzi’s EP8 ending fall scene
Today I will now be calculating the ending N & Uzi’s episode 8 fall scene where N & Uzi fall down onto copper 9 to confront Cyn.
By the ending of the fall scene, I’m specifically referring to this part where they appear to be very far up before crashing down onto one of the platforms nearby the labs unharmed.
This will be a reaction speed feat, & possibly a travel speed feat
In this scene, they both landed (even while sliding across the platform) perfectly fine.
Now we know that Uzi & N were REALLY far up before this ending-fall scene because of the scene where Uzi throws her null right before:
Not to mention that V & J- who were also very far up from copper 9’s surface (as shown below)-
-Were still barely able to see Uzi & N who were even farther away:
I think it’s also worth pointing out that:
- N moved on his own while falling to catch up with / go near Uzi right before this end-fall scene occurred. (Shown below)
And 2.) That V & J can fight eachother in space or in the very high upper atmosphere while gravity from both copper 9 & Cyn’s null was pulling them down.
This means that this calc should be a perception & reaction speed feat (since Uzi & N would’ve needed to react fast enough to perfectly land right, including the timing of landing).
But this could (possibly) count as a potential combat or travel speed feat for N as well (I don’t think so though, but it’s still a possibility).
Finding distance:
Now for actually doing the calc- distance is needed.
Since in this frame it looks like they are closer to the surface than it seems (although this can just be just because of the animation being in 3D), I‘ll be doing 3 versions:
- Assuming that in this ending of the fall scene, they fell from the troposphere. I will be using both the high latitudes in the polar regions in the winter which is 6 km (3.7 mi; 20,000 ft), and the general planet’s middle latitudes which is 11 km (6.8 mi; 36,000 ft)
- Assuming that in this ending of the fall scene, they fell from the mesosphere where falling meteors start to slow down & leave fiery trails that can be seen during the night. This would be 50 km (31 mi; 164,000ft) - 85km (53 mi; 278,871 ft)
- Assuming that in this ending of the fall scene, they were still in (the boundary of) space. Space is 100 km (62 miles) above Earth’s surface.
Finding time:
Now for finding the time. Based on the scene from here-
-up to the point where they land. That’s almost 2 seconds (but we’ll just go with 2 seconds)
Now for the results:
(This calc does not include air resistance)
Distance divided by time = speed (I will be doing this in mph)
Low-End (Troposphere):
6km / 2 seconds = 6710.81 mph (Mach 8.74 - Hypersonic
11km / 2 seconds = 12303.1 mph (Mach 16.03 - Hypersonic+
Mid-End: (Mesosphere):
50km / 2 seconds = 55923.4 mph (Mach 72.88 - High Hypersonic+
85km / 2 seconds = 95069.8 mph (Mach 123.90 - Massively Hypersonic
High-End (Boundary of space / Kármán line):
100km / 2 seconds = 111847 mph (Mach 145.77 - Massively Hypersonic)
Posted Nov 10, 2025, 7:47 AM UTC