divisible by 9?
Last week I posted a question about a trick I found to factoring a number ending in 5. Why did this trick work? The mathematicians of Reddit immediately had the answer:
Realize that a number ending in 5 can be written 10n+5. So
5q = 10n + 5,
q=2n+1 , where q is the desired factor
Brilliant minds out there. How beautiful.
Here is another question about factoring: I was told as a child that if a number has 9 as a factor, then the sum of the digits comprising the number will add up to a mulltiple of 9.
Example: 972
9+7+2 = 18, a multiple of 9
Is there some way to prove this?
Posted Apr 5, 2026, 3:03 PM UTC
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