This was my orginial power delivery schematic for the board I'm currently building.

The goal was to have a configurable USBC Power line, a buck converter to convert to 5v and an LDO from 5 to 3.3v. I picked a buck for 5, since I need to use the 5v line as power supply and I want as little heat as possible and the LDO for 3.3 since its only used for my microcontroller, for which I need little current but stability.

The components are:  
\- CH224K  
\- MP2338-GTL-Z  
\- APK2112K-3.3

I made this design before realising that I need to connect VDD and the CFG pins of the ch224k to 3.3v (which absolutely fried it).

Now I'm trying to figure out how to get 3.3v to the chip by using the same components.  
The problem is that my 5v converter needs a minimun Vin of 6.8V, which means that the default 5v from usb wont be able to power it. The LDO can take a maximum of 6.8v, which means I can't connect it to VCC either, when I want to use higher voltages.

Is there a way getting the ch224k to work with these 3 components or will I have to change some of them? I currently have 2 ideas:

1. I have a bunch of AMS1117-3.3v laying around, which should be able to handle 12-15v. Even though they would be running quite hot, they should be enough to temporarily supply the 3.3v needed, to start up the actual circuit from above.
2. I could try to find a 5v buck converter that already works at \~4.5v in, so it can supply the LDO wcwn from the default 5v and then power the ch224k

I'd love any feedback on my 2 ideas or new ways to approach this.  
Thanks in advance!

How do I supply CH224K with 3.3v?