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I have a question regarding file handling tellg() concept :

this is my code: I want to Ask in this string the Character 'H' is actually at 0 position so why in front of H it is being written 1 why not 0?

#include <iostream>

#include <fstream>

#include <string>

using namespace std;

int main() {

// 1. Setup the file

ofstream out("data.txt");

out << "HELLO WORLD"; // 11 characters

out.close();

ifstream in("data.txt");

char ch;

// 2. Initial Position (0)

cout << "Initial position: " << in.tellg() << endl;

// 3. Loop through every character

// in.get(ch) reads one char and moves the pointer forward by 1

while (in.get(ch)) {

cout << "Character [" << ch << "] read. New Position: " << in.tellg() << endl;

}

// 4. Handle the End of File (EOF)

if (in.eof()) {

cout << "Reached EOF. tellg() returns: " << in.tellg() << endl; // This will be -1

in.clear(); // Reset the 'safety switch'

cout << "After clear(), final position is: " << in.tellg() << endl; // This will be 11

}

in.close();

return 0;

}

Q2.And same this is one more code in this also the why the position of 1st character not being shown as 0?

#include<iostream>

#include<fstream>

using namespace std;

main(){

ifstream myfile;

string str;

int position;

char ch;

myfile.open("lala.txt");

while (!myfile.eof()) {

if(myfile){

// myfile>>ch;

myfile.get(ch);

position=myfile.tellg();

cout<<"Character is:"<<ch<<" "<<"at position:"<<position;

cout<<endl;

}

else{

cout<<"Something went wrong";

}}}

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Q3. last Question I am having bit confusion that why

*Character is:f at position:-1*(-1 is being shown) is being shown in end I am unable to understand