Someone help me find answer
Suppose you are standing on Earth and load your friend into a massive cannon, firing him directly toward the Moon at an initial speed of 1,000 m/s.
The cosmic layout forms a perfect right-angled triangle between you (Earth), the Moon, and the Sun:
* **The Sun** sits precisely at the right angle (90°).
* **You (Earth)** are located at the 53° angle of the triangle.
* **The Moon** is located at the 37° angle of the triangle.
* The total distance from Earth to the Moon is 50,000 m.
**The Rules of the Journey:**
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Earth's gravity is a constant 10 m/s².
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The Sun's gravity is a constant 100 m/s² and actively pulls on your friend during the entire journey.
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The Moon has absolutely zero gravity.
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The exact instant your friend touches the Moon, his forward momentum stops, and the Sun immediately sucks him straight down until he reaches it.
**Question:** How many total seconds pass from the moment the cannon is fired until your friend reaches the Sun?
*(Note: In reality, because the Sun pulls sideways while your friend flies toward the Moon, his trajectory will not be a straight line. The lateral gravitational force will deflect him into a curved parabolic path, requiring complex calculus to solve the exact flight time and precise aiming angle).*
Posted Jul 4, 2026, 6:23 PM UTC