Dice odds
I read about 5 dice that can fairly determine who goes first with one roll, no rerolls. Apparently, mathematicians needed 60-sided dice.
For 2 dice:
D1: 1,1,4,4
D2: 2,2,3,3
Each wins 50%.
I think I found a simple 5-dice solution:
D1: 1,10,14,17
D2: 2,9,15,16
D3: 3,8,13,18
D4: 4,7,11,20
D5: 5,6,12,19
Each totals 42, and every pair has 8 winning outcomes.
D1 vs D5:
D1: 1(0),10(2),14(3),17(3)=8
D5: 5(1),6(1),12(2),19(4)=8
They seem balanced. This feels WAY too easy compared with the 60-sided solution. What am I missing?
Posted Sep 5, 2026, 3:56 PM UTC
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