Since I wrote this out in a comment, might as well post it. The holographic mass and proton rest mass deduction starting with only proton charge radius, planck length, planck mass - all sourced.

Proton charge radius: .8755 x 10^-16 m

Proton volume with given radius: 2.831 * 10^-45 m^3

Planck length diameter sphere volume: 2.21 * 10^-105 m^3

Divide them and multiply by planck mass

((2.831 * 10^-45 m^3) / (2.21 * 10^-105 m^3)) * planck mass

Yields: 1.281 * 10^60 * planck mass = 2.788 * 10^55 grams.

And here is calculating the proton rest mass via these same principles but applying the holographic principle (planck masses that fit on surface / planck spheres in volume)

Surface Plancks on proton area with proton charge radius : 4.71 * 10^40

Surface Plancks times planck mass: 1.02656 * 10^36 gram

That is the mass of the 'surface horizon' of the proton.

Now all we have to do is divide by the plancks that would fit inside:

2 * (surface horizon mass / planck units in volume)

2 * (1.02656 * 10^36 gram / 1.2804 * 10^60) = 1.603498 * 10 ^-24 grams