[Differential Equations] homogeneous DE to and exact DE with an integrating factor.

The general homogeneous DE \frac{dy}{dx}=h(\frac{y}{x}) can me rewritten as h(\frac{y}{x})dx-dy=0 Assuming h(z) not = z show that the integrating factor u=\frac{1}{xh(\frac{y}{x})-y} makes the rewritten DE and exact DE

Imgur link