[Differential Equations] Separable Equations

RESOLVED

I'm given (t^2 -26t +120)dy/dt = y such that y(13) = 1. Separating and beginning to integrate I get ln(y) = ∫ 1 / (t^2 -26t +120) dt. I factor and get (t-6)(t-20), now using partial fraction decomp I get (1/14) ∫ 1/(t-6)dt + (-1/14) ∫ 1/(t-20) dt which should be 1/14 ln(t-6) - 1/14 ln(t-20) + C If I set this equal to 1 and sub 13 for t, I get -1^(1/14) which can't be. I don't know where I've gone wrong.

Edit: dt not dx

Posted Apr 15, 2016, 1:17 AM UTC · edited

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