derivative correct?
f(x) = (x^2 /(x-1))^x
ln f(x) = x(ln x^2 - ln (x-1))
f'(x) = ((ln x^2 - ln(x-1))+ x(2/x - 1/(x-1)))* ((x^2 /(x-1))^x
Posted Apr 15, 2016, 2:36 AM UTC · edited
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f(x) = (x^2 /(x-1))^x
ln f(x) = x(ln x^2 - ln (x-1))
f'(x) = ((ln x^2 - ln(x-1))+ x(2/x - 1/(x-1)))* ((x^2 /(x-1))^x
Posted Apr 15, 2016, 2:36 AM UTC · edited