Okay so in Calc 2 I was told to find the area of the region between the functions f(x)=Cos(2x) and g(x)=Sin(x) between x= -pi/2 and x=pi/6. The calculus part is not what I'm having problems with. I used the formula Integral{f(x)-g(x)}dx, simplified and integrated. I got 1/2{sin(2(pi/6))+cos(pi/6)}-1/2{sin(2(-pi/2)+cos(-pi/2)}. After the trig, I get 1/2{sqrt(3)}-1/2{0} my final answer being sqrt(3)/2. But that's not right, according to Wolfram Alpha. Help is appreciated. Thanks.
Link: https://www.wolframalpha.com/input/?i=area+between+curves&rawformassumption=%7B%22F%22,+%22AreaBetweenCurvesCalculator%22,+%22f1%22%7D+-%3E%22cos(2x)%22&rawformassumption=%7B%22F%22,+%22AreaBetweenCurvesCalculator%22,+%22f2%22%7D+-%3E%22sin(x)%22&rawformassumption=%7B%22F%22,+%22AreaBetweenCurvesCalculator%22,+%22variable%22%7D+-%3E%22x%22&rawformassumption=%7B%22F%22,+%22AreaBetweenCurvesCalculator%22,+%22rangestart%22%7D+-%3E%22-pi%2F2%22&rawformassumption=%7B%22F%22,+%22AreaBetweenCurvesCalculator%22,+%22rangeend%22%7D+-%3E%22pi%2F6%22&rawformassumption=%7B%22C%22,+%22area+between+curves%22%7D+-%3E+%7B%22Calculator%22%7D