[Probability] Probability of being dealt a straight flush using random sampling?
Hey r/learnmath! I need to find the probability of being dealt a straight flush where we assume all 52 choose 5 hands are equally likely. I need to use the equation that P (g good and b bad) = (G choose g)(B choose b) divided by (N choose n) where N is size of the population that contains G good and B bad elements and N = G + B. Furthermore, n is the sample of size n=g+b, where 0≤g≤n.
I tried doing N=52, n=5, G=13, g=5, B=39, and b=0 and I got the wrong answer. I think my attempt gets me the probability of getting 5 cards of the same suit, but I'm not sure how to get the 5 consecutive bit.
Posted Feb 17, 2017, 2:29 AM UTC
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