me÷irl
Posted May 31, 2018, 5:49 PM UTC
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I always knew he was a sin(ner)
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This is legit how i remembered this trig identity for years
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actually bill^2+(bill*by)sin+(bill*by)+by^2
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Cos= adjacent over hypotenuse
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Ew math
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Shouldn't it be Bill (Sin/Tan)by so that Bill*by doesn't cancel out on top I mean ^me ^too ^thanks
More like BillSinby/Tanb because SinA/Ta nA = CosA