I don't understand the wiring in my guitar. I'm fine with the tone and volume, but what I dont understand is the bridge black wire seems to be connected to the switch output. The pickups use SD wiring colours.
Wouldn't this mean in each position, the bridge pickup is in the signal?
Posted Aug 12, 2018, 11:24 AM UTC · edited
Also is there anywhere to learn more about what the 4 colours of a humbucker are...
https://guitarelectronics.com/guitar-wiring-resources/humbucker-wire-color-codes/
... and some more interesting wiring options?
https://www.seymourduncan.com/blog/the-tone-garage/guitar-wiring-diploma-course
https://www.scribd.com/doc/2154081/Craig-Anderton-Guitar-Electronics-for-Musicians
These links are superb. Thank you so much.
Also is there anywhere to learn more about what the 4 colours of a humbucker are, and some more interesting wiring options?
I'd need to get my head round it. The short version is that the wires are the start and end of each coil. With four wires you have the option of just using one coil 'splitting', you can have the end of one coil feeding into the other 'series' which is the 'normal' wiring, or have the start of each coil joined together and the end of each coil joined together 'parallel'. To be honest looking at the switching diagram your guitar seems to sprinkle a few of these things in already.
Yes that makes sense actually.
The bridge black wire isnt connected to the output, as the output is on pins 0 (opposite side) and 1 on the other. This wiring allows for the humbuckers to be split; neck only in position 2 and neck and bridge in parallel in position 4. Otherwise its standard HH wiring. Ibanez does something very similar for their HH, 5 way switch guitars.
Oh so it’s arbitrary pin numbering? I thought 0 was always connected? Right I see, thanks!!