This one's pretty easy. You get the length of the lower diagonal from r cos theta = x and then the height of the bakery from y = r sin theta. Length of the upper diagonal and difference between the two building heights same way. Third angle from tan theta = y / x.

Sounds like your just trying to find the "back" side of both triangles and add them together to get the height of the office building.

So add [250sin(17)]/sin(73)  +    [250sin(23)]/sin(67). I believe that should get you your answer. If you need me to explain how I got that let me know.

How do I do this