Did you try using the Pattern and Matcher classes from Java? Something like:

    import java.util.regex.Pattern;
    import java.util.regex.Matcher;

    
    Pattern p = Pattern.compile("([0-9]{7})");
    Matcher m = p.matcher(inString);

    // find 2nd instance of pattern and print it
    if (m.find() && m.find()) {
        System.out.println(m.group(1));
    }


Did you try using the Pattern and Matcher classes from Java? Something like:

    import java.util.regex.Pattern;
    import java.util.regex.Matcher;

    
    Pattern p = Pattern.compile("([0-9]{7})");
    Matcher m = p.matcher(inString);

    // find 2nd instance of pattern and print it
    if (m.find() &amp;&amp; m.find()) {
        System.out.println(m.group(1));
    }


I'm trying to pull a seven digit number out of a string of text. I only need the number but the text before and after it will change every time. I'm reading the html in line by line but need to only get the second 7 digit number from this string

&lt;/td&gt;&lt;td align="left" width="15%" class="text"&gt;&lt;a CLASS="Bcruising" HREF="&amp;#xA; javascript:EditMember(2566802,2966456)&amp;#xA;					"&gt;Usernamexxx&lt;/a&gt;

I would use this command in bash "egrep -o '[0-9]{7}' " and am looking for something similar in java.

Any help would be very appreciated :) 

Regular expressions help!