I am so lost with this question I'm not even sure where to begin. Any help would be appreciated.
Determine one possible value for x when 0<x<2pi.
sin8pi/23=sinx
x cannot equal 8pi/23
Posted Feb 28, 2022, 11:57 AM UTC
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Title: Trig angle question, not sure where to begin with this one.
Full text:
I am so lost with this question I'm not even sure where to begin. Any help would be appreciated.
Determine one possible value for x when 0<x<2pi.
sin8pi/23=sinx
x cannot equal 8pi/23
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you can do arcsin both sides and get x= 8pi/23. but you know since is only positive in QI and QII so find an equivalent angle to 8pi/23 in QII.
That's where I'm confused, the only way I know how to work with compound angles is if they are from the two special triangles. So pi/6, pi/4, pi/3. I can build something like sinpi/12 with sin(pi/3-pi/4) but how am I supposed to build 8pi/23?
[deleted]
don't really follow what you're saying. if you know it's 8pi/23 from 0 radians. then just find something that is 8pi/23 from pi radians. so do pi-8pi/23. that's your answer